Rotational motion, Pulley system

  • Thread starter zames99
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  • #1
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Homework Statement


A 5kg mass and a 10kg mass are connected by a rope and hung over a pulley. The pulley is a disc with a mass of 5kg and a radius of 10cm. the two masses are initially at rest with the 10kg mass 50cm higher than the 5kg mass.
Find, The speed of each mass at the instant they pass one another
The torque exerted on the pulley by the masses
The angular momentum of the pulley at the instant the masses pass one another.

Homework Equations


L = m(r * v)
T = r * F
I(disc) = 1/2 mv^2


The Attempt at a Solution


Part (1)
F=(10-5)*9.8 = 49N
Mtotal = (10+5)=15
a =49/15 =3.26 ms^-2
v^2 = 0^2 + 2 * 0.5 * 3.26
v = 1.8 m/s

Part (2)
The only external forces acting on the disc are m1*g and m2*g
T = r * F
T = r (m2*g-m1*g)
T = 0.1 (10*9.8-5*9.8)
T = 4.9 Nm

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Filip Larsen
Gold Member
1,440
348
Your answer to part 1 does not look correct. Assuming no frictional losses, you may find it helpful to equated the mechanical energy (i.e. the sum of potential and kinetic energy) of the three masses before they are released with the mechanical energy of the system when the two masses pass each other. Doing that, you should arrive at a speed around 1.11 m/s.

Your answer to part 2 looks correct.
 

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