Rotational Speed/Linear Speed help, need confirmation

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SUMMARY

The discussion centers on calculating the linear speed of a 4 kg block falling from a height of 10 meters and the number of revolutions made by a 1050 g iron disc with a radius of 40 cm. The user applied the energy conservation equation, mgh = 0.5m1v² + 0.5Iω², where I is the moment of inertia calculated as I = 1.050 * 0.4² * 0.5. The user corrected the mass used in the equations, confirming that the mass in mgh should be 4 kg, while the total mass for kinetic energy calculations should be 5.05 kg.

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Homework Statement



A 4 kg block, 10m above the ground is attached to a long cord which is wrapped around a 1050 g iron disc of radius 40 cm. The system is originally at rest, afterwards the block is let go and allowed to fall. From the time the block is let go to when the block crashes with the ground, calculate the speed of the block as it hits the ground
the number of revolutions the disc makes

Homework Equations



energy equations

The Attempt at a Solution



For the linear speed as it hits the ground i used

mgh = .5m1v2 + .5Iω2

Where I = 1.050*.42*.5
m1 is the mass of the disc + the block, so 1.050+5kg = 5.050 kg
I replaced ω with v/r, to have the equation

mgh = .5mv2 + .5I(v/r)2

Is this correct?

For the revolutions, I would probably use

θ = ωt + .5αt2, where t = (ωf - ωi)/α

is this part correct?

Thanks
 
Last edited:
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The m in your mgh should be 4 kg as that is the mass that falls to the ground? I'm confused with the number you wanted to use for m.
 
Oh god my bad sorry, I meant the m in .5 mv^2 should be 4+1.050, so 5.05, idk where i got 1.5 from, i replaced m1 with the mass in .5mv^2, and mgh has a mass of 4 as you said. Sorry for the confusion
 

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