Rotational and angular speed problem

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SUMMARY

The discussion focuses on solving a rotational dynamics problem involving a solid disc with a radius of 60 cm and a moment of inertia of 40 kg m², subjected to a constant tangential force of 50 N. The mass of the disc is determined using the moment of inertia formula, yielding a mass of 80 kg. After 4 seconds, the angular speed is calculated using rotational kinematic equations, resulting in an angular speed of 10 rad/s, and the disc completes approximately 20 revolutions. The kinetic energy at 4 seconds is shown to equal the work done by the external force, confirming the relationship between work and kinetic energy in rotational motion.

PREREQUISITES
  • Understanding of moment of inertia, specifically for solid discs.
  • Familiarity with rotational kinematic equations, including angular acceleration and angular speed.
  • Knowledge of torque calculations and their relation to force and distance.
  • Ability to apply kinetic energy formulas in rotational contexts.
NEXT STEPS
  • Study the derivation and application of the moment of inertia for various shapes, focusing on solid cylinders.
  • Learn about the relationship between torque, angular acceleration, and moment of inertia in rotational dynamics.
  • Explore the concept of work-energy principles in rotational motion, including calculations for different scenarios.
  • Investigate advanced rotational kinematic equations and their applications in complex systems.
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics and rotational dynamics, as well as engineers involved in designing rotating systems.

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Homework Statement


A constant force of 50 N is applied tangentially to the rim of a solid disc with a 60cm radius. The wheel has a moment of inertia of 40 kg m^2

a) what is the mass of the disc?
b) 4 seconds after starting from rest, what angular speed does it have?
c) How many revolutions does it complete in 4 seconds?
d) Show by explicit calculation that the kinetic energy of the wheel when t = 4 is equal to the work done upon the wheel by the external force from t = 0 to t = 4.


Homework Equations



I = [itex]\beta[/itex] M R^2
[itex]\omega[/itex] = Δθ / s
Ʃ[itex]\tau[/itex] = I[itex]\alpha[/itex]

KE(rotation) = 1/2(rotational mass)ω^2

The Attempt at a Solution



For part a, which I think seems easy, is I apply the moment of inertia equation to solve for mass? but what I don't understand is what is the β part, in my notes it is the "form function" but in the problem statement it is not noted anywhere?

For part b and c, I'm thinking I can apply one of the rotational kinematic equations (ωf = ωo + [itex]\alpha[/itex]t ) where alpha is [itex]\tau[/itex] = I[itex]\alpha[/itex], but the part I am confused on is if I use the constant force of 50N for the summation of the torque forces? if so I can use that to find the rotational acceleration and just apply the rotational kinematic equations and be able to solve the question.

part d, I'm having trouble on this one, I'm thinking if the acceleration is as mentioned above, I believe I can calculate the angular speed at t = 4s, apply it to the rotational kinematic energy equation, and then compare that to the work = ΔKE ?
 
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a) If you look up the equation for the moment of inertia for a solid cylinder you will see that it is I = MR2/2 so β for a cylinder is 0.5.

http://en.wikipedia.org/wiki/List_of_moments_of_inertia

b)&c) Remember Newtons F=ma ? Well for rotation there is the similar equation ...

Torque = moment of inertia x angular acceleration
and
Torque = force * distance = 50 * 0.6

they yes you apply the rotational rotational kinematic equations.

d) Yes. If this was a linear problem you would show that

Work applied = kinetic energy of the object
eg
Force * distance = 0.5 mass * velocity2

Write the equivalent for rotation.

The earlier parts of the question give you some numbers to plug in.
 

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