Rotational-Vibrational Spectroscopy: P,Q,R Branches

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Discussion Overview

The discussion revolves around the P, Q, and R branches in rotational-vibrational spectroscopy, focusing on the conditions under which Q branch transitions, characterized by "delta J = 0," are allowed. Participants explore the implications of these transitions in the context of molecular models and selection rules.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant explains that the P-branch corresponds to "delta J = -1" and the R-branch to "delta J = +1," while expressing confusion about the Q branch and its conditions for being allowed.
  • Another participant notes that the condition for "delta J = 0" is derived from the rigid rotor model, suggesting that deviations from this model may allow for Q branch transitions.
  • A different viewpoint is introduced, indicating that electronic angular momentum can also lead to "delta J = 0" selection rules, particularly during electronic transitions between different states, where photon angular momentum is transferred to electronic degrees of freedom instead of rotational motion.

Areas of Agreement / Disagreement

Participants express varying perspectives on the conditions for Q branch transitions, with no consensus reached on the specific scenarios under which these transitions are allowed.

Contextual Notes

The discussion highlights the dependence on the rigid rotor model and the potential limitations of this model in explaining Q branch transitions, as well as the complexities introduced by electronic transitions.

photon79
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In rotational-vibrational spectroscopy P-branch corresponds to low level rotational transitions "delta J = -1" and R-branch to high rotations "delta J = +1". And I am confused about Q branch which corresponds to "delta J = 0" ; which means that no rotational change is there and it is allowed in some cases. I want to know when it is allowed and how?. Because when vibrational or electronic transitions are there rotational quantum number should change.
 
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The condition that delta J = 0 is derived from the rigid rotor model. Molecules that are not well approximated by the rigid rotor model can therefore potentially exhibit Q branch transitions.

Claude.
 
Hi claude...thanks for the replies, I got some thing out of them,.
 
Always good to know :wink: .

Claude.
 
Though its not the case you mentioned, it is also possible that electronic angular momentum may yield a \Delta J = 0 selection rule. This may occur when a rotational transition accompanies an electronic transition between, say, a \Sigma singlet state to a\Pi singlet state. In this case, the photon angular momentum is transferred to the electronic degrees of freedom as opposed to the rotational motion of the nuclei.
 

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