S domain analysis problem, just need a little help

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The discussion focuses on solving nodal analysis equations for voltages v1 and v2 in a circuit involving a 2Ω resistor and a current source. The initial equations presented for v1 and v2 were corrected, emphasizing that the 2Ω resistor does not affect the current from the V2 node. The correct expression for v2 was clarified to be ((v1-v2)/(5/s)) - v2/2s - 5/s, following adjustments to capacitor impedance calculations.

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Okay i need to find expressions for v1 and v2 and I am using nodal analysis:

these are not the final the equations just initial equations by first look


I am good finding expression for v1,
(2/s)-(v1/1)-((v1-v2)/(2/s)) = 0

Where i am stuck is with the current source and 2 ohm res. in series

For v2,
((v1-v2)/(2/s))-(v2/2s)-(v2/2)-(5/s) = 0 this is my derivation that I am unsure of

the reason i think this is wrong for v2 is in my head i see instead of v2/2 - 5/s i see something like ((v2-v)/2)-(5/s)? where v is voltage between current source and res

Can anyone help me understand where I am right or wrong thanks

**BTW see attachment for circuit**
 

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For nodal analysis you're only concerned with summing the currents. The 2Ω resistor in series with the 5u(t) current source is not going to alter that current that it pulls from the V2 node. So ignore the resistor!

FYI, your entries for the capacitor impedance look a bit off. 1/(s*200 mF) should yield something like 5/s.
 
so would v2 be:

((v1-v2)/(5/s)) - v2/2s - 5/s?

my mistake on the cap transformation it is 5/s which is equal to 1/0.2s my bad
 
Derill03 said:
so would v2 be:

((v1-v2)/(5/s)) - v2/2s - 5/s?

my mistake on the cap transformation it is 5/s which is equal to 1/0.2s my bad

That looks fine :smile:
 

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