Sagnac Effect and Special Relativity

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SUMMARY

The discussion centers on the Sagnac effect and its implications for special relativity (SR). Participants clarify that while the Sagnac effect involves light traveling in a circular path with a rotating observer, it does not contradict the constancy of the speed of light (c). The local velocity of light remains c in inertial frames, while in non-inertial frames, such as those experiencing rotation, the observed speed can vary. The conversation also references the mathematical framework of time dilation and the use of MAPLE for calculations related to the Sagnac effect.

PREREQUISITES
  • Understanding of special relativity principles
  • Familiarity with the Sagnac effect
  • Basic knowledge of time dilation and inertial vs. non-inertial frames
  • Proficiency in using MAPLE for mathematical computations
NEXT STEPS
  • Study the mathematical derivation of the Sagnac effect using MAPLE
  • Explore the implications of non-inertial frames in special relativity
  • Review Maxwell's equations in the context of special relativity
  • Investigate experimental setups that demonstrate the Sagnac effect
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Physicists, students of relativity, and anyone interested in the interplay between the Sagnac effect and special relativity will benefit from this discussion.

KingNothing
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http://www.mathpages.com/rr/s2-07/2-07.htm

Today I met a man who was claiming that the Sagnac effect, particularly in the case of light moving in a circular pattern with a rotating observing "arm" as in the first figure in the link, is contrary to special relativity. He claimed that since the wave will hit the observing arm at a rate of c+v or c-v, that this contradicts the constancy of c.

Now, in my head, I am thinking that this speed of c+v is what we observe from our inertial system which holds the axis of the roation constant, but that an actual observation device placed on the arm would still observe the incoming light as having a speed of 3*10^8 m/s.

Is this to be explained by a slight time dilation, making the time difference in the frame of the observer located on the moving arm equal to the time difference observed by us in the reference frame holding the axis constant?

y = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}
 
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Actually, I have been staying up all night working on this problem. I will post the solution when I am finished.
 
I've made a brief MAPLE worksheet demonstrating just one calculation to show that the Sagnac effect does not imply an inconstancy in the speed of light. Please see the attached PDF.
 

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KingNothing said:
Now, in my head, I am thinking that this speed of c+v is what we observe from our inertial system
I think you have it backwards. Inertial frames always observe light traveling at c. In the rotating (non inertial) frame the speed of light can vary. That is what SR says and has been observed so far.
 
The webpage you quoted contains the time correction in there, but good job on going through the math yourself.
 
A.T. said:
Inertial frames always observe light traveling at c. In the rotating (non inertial) frame the speed of light can vary. That is what SR says and has been observed so far.
Exactly. Although, the LOCAL velocity of light is allways equal to c, even for rotating and accelerating observers. That is, if you measure the velocity of light traveling NEAR you, you will allways get c. But in the Sagnac effect you don't measure the local velocity of light.

See also Sec. 6 of
http://xxx.lanl.gov/abs/gr-qc/9904078 [Phys.Rev. A61 (2000) 032109]
 
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What is the structure that is described (propagating) in Special Relativity (Maxwell's equations?). Is there an induction experiment that emits light?
 
amyfrog said:
What light is used?


A laser
 
The Sagnac effect does not make any statement about SR nor does it depend upon GR for an explanation. You can get a time difference by setting up 4 mirrors each at the corner of a rectangle at an angle of 45 degrees - now put a source/receiver in one leg of the path so two beams travel in opposite directions around the path - now rotate the entire frame about an axis perpendicular to the plane of laser path(s) and there will be a difference in the time between the arrival of the photons because one photon has had to travel a longer distance to reach the moving receiver - but the same follows if you don't rotate the experiment, but simply move the transceiver linearly along one leg relative to the frame of the mirrors - the beam which is reflected by the mirrors in the clockwise direction will take a different amount of time than the counter-clockwise beam because one beam has to travel further to catch the receiver than the other
 

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