Scale in an elevator physics problem

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Homework Help Overview

The problem involves a scenario where a girl weighs herself on a scale in an elevator that is ascending but decelerating. The subject area relates to forces, specifically gravitational force and apparent weight in a non-inertial reference frame.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the forces acting on the girl and the implications of the elevator's acceleration on the scale reading. There are attempts to clarify the deceleration of the elevator and its effect on the weight measurement.

Discussion Status

The discussion is active, with participants exploring different aspects of the problem, including the calculation of gravitational force and the effects of acceleration on the scale reading. Some guidance has been provided regarding the need to consider forces and acceleration, but no consensus has been reached on the final answer.

Contextual Notes

Participants note the given values in the problem, including the girl's mass and the elevator's deceleration, while questioning the assumptions about the forces involved.

conniechiwa
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A 62-kg girl weighs herself by standing on a scale in an elevator. What does the scale read when the elevator is ascending at 11 m/s but its speed is decreasing by 5 m/s in each second?

I'm not really sure where to begin.
 
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conniechiwa said:
A 62-kg girl weighs herself by standing on a scale in an elevator. What does the scale read when the elevator is ascending at 11 m/s but its speed is decreasing by 5 m/s in each second?

I'm not really sure where to begin.

Hint, you need the force exerted by the girl on the scale... that's the weight the scale reads...

You also know that the force the girl exerts on the scale = the force the scale exerts on the girl.
 
Well I know that normally the scale would read 608.5 N if the elevator was not moving, but I'm not sure what to do here.
 
conniechiwa said:
A 62-kg girl weighs herself by standing on a scale in an elevator. What does the scale read when the elevator is ascending at 11 m/s but its speed is decreasing by 5 m/s in each second?

I'm not really sure where to begin.

First, find what the deceleration of the elevator is.
 
conniechiwa said:
Well I know that normally the scale would read 608.5 N if the elevator was not moving, but I'm not sure what to do here.

draw the freebody diagram of the girl... what are the forces acting on the girl... you know that \Sigma\vec{F} = ma. follow l46kok's suggestion and find the acceleration of the girl.
 
Would the deceleration be -3.45 m/s squared?
 
conniechiwa said:
Would the deceleration be -3.45 m/s squared?

No, the deceleration is the same given in the question...
 
only the velocity is given?
 
conniechiwa said:
only the velocity is given?

They give 5m/s per second... so the acceleration is -5m/s^2
 
  • #10
iidesjo!

okay,

Fg=m*g (Fg is gravitational force)
Girl weighs (m) 62 [kg].
Gravitational constant (g) is 9.81 [m/s^2]
Fg= 62*9.81= 608.22 [N]
that is the static value.

With F=m*a you can calculate the difference in force compared to static (v=c)
a= -5 [m/s^2]
F= 62*-5= -310 [N]

so the scale will indicate 608.22-310= 298.22 [N]
to calculate back to mass divide through the graviotational constant.
298.22/9.81= 30.4 [Kg]
you're welcome!
:D
 

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