Second Law of Thermodynamics problem

Click For Summary
SUMMARY

The discussion centers on calculating the minimum theoretical mass flow rate for a power cycle with a net power output of 1 MW, utilizing heat transfer from steam condensing at 100 kPa and discharging heat to a lake at 17°C. The efficiency of the cycle is calculated using the formula 1 - (Tc/Th), yielding an efficiency of approximately 0.2204. The user derives a heat input (Q) of approximately 4,536,585.4 J and subsequently calculates the mass flow rate, arriving at a value of approximately 1566.25 kg/s. The user seeks confirmation on the correctness of their calculations.

PREREQUISITES
  • Understanding of the Second Law of Thermodynamics
  • Familiarity with thermodynamic cycles and efficiency calculations
  • Knowledge of heat transfer principles, particularly phase changes
  • Proficiency in using enthalpy values in thermodynamic equations
NEXT STEPS
  • Study the derivation of the Carnot efficiency formula in thermodynamic cycles
  • Learn about the calculation of mass flow rates in heat exchangers
  • Explore the implications of heat transfer to bodies of water in thermodynamic systems
  • Investigate the use of enthalpy tables for various substances in thermodynamic analyses
USEFUL FOR

Students and professionals in thermodynamics, mechanical engineers, and anyone involved in the design and analysis of power cycles and heat transfer systems.

aliaze1
Messages
173
Reaction score
1

Homework Statement



As shown in the figure, a system undergoing a power cycle develops a net power output of 1MW while receiving energy by heat transfer from steam condensing from saturated vapor to saturated liquid at a pressure of 100 kPa. Energy is discharged from the cycle by heat transfer to a nearby lake at 17 deg. C. These are the only significant heat transfers. Kinetic and potential energy effects can be ignored. For operation at steady state, determine the minimum theoretical mass flow rate, in kg/s, required by any such cycle.

l_fa9580eece1942bfb437f74ec4e78486.jpg

Homework Equations



(the book has letters with dots above them, these are represented by 'd')

dW = dQH-dQC
l_3c57a33c37ca42b6acadd05371bce2b4.jpg
(equals zero)

The Attempt at a Solution


So I just did this problem again, and here is what I get:

I calculate efficiency, which is 1-(Tc/Th), T being in Kelvin. I get 41/186, or ~0.2204

Then I use the formila Q=W/n, n is efficiency, so it is 1000000/(41/186) = ~4536585.4

Then plugging this Q into the mass flow formula, where gz and V^2/2 are zero:

4530585.4-1000000+m(2675-417), 2675 and 417 being enthalpy values at the states given

I get a negative number, but mass flow rate can't really be negative per say, so I end up with m=1566.2468

Am I right?Thanks!
 
Last edited:
Physics news on Phys.org
I updated the problem with my current solution (or what I think is the solution)

Please let me know if I am on track

Thanks!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 46 ·
2
Replies
46
Views
7K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K