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Second moment of area about the horizontal axis

  1. Mar 10, 2013 #1
    Could someone help me on how to calculate the second moment of area of the beam in the figure below?

    ImageUploadedByPhysics Forums1362933459.410910.jpg

    Thank you
     
  2. jcsd
  3. Mar 10, 2013 #2

    tiny-tim

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    hi vtaela! :wink:

    divide it into parts, and add the moment of area of each part

    show us what you get :smile:
     
  4. Mar 10, 2013 #3
    my calculations give me 172.8 *10^6 mm^4

    is that correct?

    thank you
     
  5. Mar 10, 2013 #4

    nvn

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    vtaela: Excellent work. Your answer is correct.
     
  6. Mar 11, 2013 #5
    I am trying to find my local variables in order to calculate the shear flow! I have the local variables as shown below! Are my local variables set correct?
    ImageUploadedByPhysics Forums1363000995.952013.jpg
    Thank you
     
  7. Mar 11, 2013 #6

    nvn

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    Looks reasonable.
     
  8. Mar 31, 2013 #7
    I finished with this, look similar to what you got?
     

    Attached Files:

  9. Mar 31, 2013 #8
    Working out of ixx
     

    Attached Files:

  10. Mar 31, 2013 #9
    Flow diagram and calculation of s1
     

    Attached Files:

  11. Mar 31, 2013 #10
    Calc of s2, s3 and s6. The first picture i posted is calc for s4 and final value. Any idea how to do shear centre?
     

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