Second moment of area about the horizontal axis

AI Thread Summary
To calculate the second moment of area for a beam, divide it into parts and sum the moments of area for each section. One participant confirmed their calculation of 172.8 * 10^6 mm^4 as correct. The discussion then shifted to determining local variables for calculating shear flow, with participants sharing their calculations and results. There was also a query regarding how to find the shear center. The conversation reflects a collaborative effort to solve beam analysis problems.
vtaela
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Could someone help me on how to calculate the second moment of area of the beam in the figure below?

ImageUploadedByPhysics Forums1362933459.410910.jpg


Thank you
 
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hi vtaela! :wink:

divide it into parts, and add the moment of area of each part

show us what you get :smile:​
 
my calculations give me 172.8 *10^6 mm^4

is that correct?

thank you
 
vtaela: Excellent work. Your answer is correct.
 
I am trying to find my local variables in order to calculate the shear flow! I have the local variables as shown below! Are my local variables set correct?
ImageUploadedByPhysics Forums1363000995.952013.jpg

Thank you
 
Looks reasonable.
 
I finished with this, look similar to what you got?
 

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Working out of ixx
 

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Flow diagram and calculation of s1
 

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  • #10
Calc of s2, s3 and s6. The first picture i posted is calc for s4 and final value. Any idea how to do shear centre?
 

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