- #1

Illusionist

- 34

- 0

## Homework Statement

Consider the second order differential equation y'' - 4y' + 4y = f(x)

Find a particular solution if f(x) = 25cos(x)

## Homework Equations

I believe for this type of question I should let y = Asin(x) + B cos(x)

Hence y' = Acos(x) - Bsin(x) and

y'' = -Asin(x) - Bsin(x)

## The Attempt at a Solution

I think everything above is right, and for the rest of the question I should just be able to substitute back into the original formula and find values for A and B.

The problem is when I do substitute back in all I get is a mess and a headache!

Here is what I got by substitution:

-Asin(x) - Bcos(x) - 4[Acos(x) - Bsin(x)] + 4[Asin(x) + Bcos(x)] = 25cos(x)

Hence

-Asin(x) + 4[Asin(x) + Bsin(x)] - Bcos(x) - 4[Acos(x) - Bcos(x)] = 25cos(x)

That's about all I think I can do and I have no idea how to obtain values for A and B. I know the answer is y(p) = 3cos(x) - 4sin(x).

How to get this answer from the above I have no idea, I'm obviously missing something.

Thanks in advance for any advice or help.