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Second Uniqueness Theorem - griffiths

  1. May 31, 2010 #1
    sorry about my English

    1. The problem statement, all variables and given/known data
    In Purcell 3.7 (Problem) and Griffith there is a question,look at fig.
    (we have 4 conductors with charges +Q,-Q,+Q,-Q (b),what will happen
    if we connect them with tiny wires in pairs )
    Griffith say that c distribution of charge ,can't be a solution
    why ?
    "because there is 2 conductors ,with total charge 0 on each ,
    one possible way to distribute zero charge over is to have no
    accumulation of charge anywhere " by Second Uniqueness Theorem
    d is the solution


    2. Relevant equations
    I know that d is a solution , but c could be a solution too ,
    why we choose d to be the solution ??
    Uniqueness Theorem say that if you found one is unique,
    and we found two.

    i could say c is a solution ,
    "because there is 2 conductors ,with total charge 0 on each ,
    one possible way to distribute zero charge over is to have
    minus charge and pluses charge at the "ends" ....
    by Second Uniqueness Theorem
    c is the solution


    3. The attempt at a solution
    ?
    help
     

    Attached Files:

  2. jcsd
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