john_Stm said:
hi firestorm , thanks for your response .. i am curious in finding the angle using the two vertical components .. x kg and y kg from my sensor outputs..
I'm not clear if you're asking me to solve it for you, but I'll absolutely get you started:
To begin, I don't think we have enough information to solve the problem, so I'm going to make some assumptions about the geometry, and we'll go from there.
First, let's define
P as the location of the pivot. We'll define
CM as the center of mass of the object on the two sensors, plus any anything else the sensors are supporting, such as a plate on which you place the object. For the sake of simplicity, we'll assume that the center of mass is directly over the pivot when the tilt angle,
θ, is 0. We'll further assume that the sensors are equidistant from the pivot, at distance
l. Finally, the distance between C
M and P is the length h.
I'll assume that the sensors exclusively measure force parallel to theta, that is, they rotate on the pivot and measure the full downward force only when θ is 0. If that's the case, we then know that the sum of the measures of the two sensors will equal the cosine of theta times weight: F
1+F
2=cosθ * m * g
We additionally know that at a certain angle of θ, which we will call \varphi, the C
M is directly over a given sensor, such that either F
1=mg and F
2 = 0, or visa versa for -\varphi.
When theta is 0, F
1=F
2=mg/2
See if you can't get started with that setup, and let me know if you have trouble, or any of my assumptions are invalid.