Self inductance of a solonoidal coil

AI Thread Summary
The discussion revolves around calculating the self inductance of a solenoidal coil with 2000 turns that generates a magnetic field of 3mT at 1A current, given a cross-sectional area of 2*10^-3 m^-2. Additionally, it addresses the mutual inductance between this solenoid and a smaller coil with 10 turns and a cross-sectional area of 4*10^-5 m^2 placed at its center. Participants express confusion about how to utilize the provided data, particularly regarding the electromotive force (emf) and the relevance of the area in the calculations. The key equations mentioned include emf=-Nd(flux density)/dt and L=flux density/current, with a query about the application of B=U0*NI/L. The discussion highlights the need for clarity on how to approach these inductance calculations effectively.
samblue
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Homework Statement



A long, solonoidal coil with 2000 turns produces a B field pf 3mT at its center when a current of 1A flows through the coil. If the cross sectional area of the coil is: 2*10^-3 m^-2, and the field is uniform throghout the solonoid, determine the self inductance of the oil.

A small coil, C, is now plaed in the middle of the solonoid as such that the axis of the coils concide. The coil C has 10 turns, and a cross setional area of 4*10^-5m^2. Calculate the mutual inuctance between C and the solenoid.

Homework Equations



emf=-Nd(flux demnsity)/dt

L=flux density/current

The Attempt at a Solution



Dont really have many ideas about this question. I cannot work out how I am going to be able to use the data given as I do not know the emf?
thanks
 
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On a second though to I have to use the formula:

B=U0*NI/L

If I do why am I given the area?
 
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