1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Sequence and Series, finding relationship

  1. Nov 25, 2007 #1
    1. The problem statement, all variables and given/known data


    in general

    2. Relevant equations


    3. The attempt at a solution

    I have no idea
    I tried to solve for Xn and substituting that into another equation...
    however, I don't know how to simplify it down to one single variable....

    How do I take the limit of the sequence, so that I can find the relationship
  2. jcsd
  3. Nov 25, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper

    Please state the problem as it is given.
  4. Nov 25, 2007 #3
    the problem was given that way, we are trying to find the relationship between X and y
  5. Nov 25, 2007 #4


    User Avatar
    Homework Helper

    take the general equations and sub one into the other is all i can suggest
  6. Nov 26, 2007 #5


    User Avatar
    Staff Emeritus
    Science Advisor

    Since there was NO X or Y in what you gave, I don't see how that can be true.
  7. Nov 26, 2007 #6


    User Avatar
    Homework Helper

    Hmm, I think I got what you mean.

    Given 0 < y0 < x0, the sequence (xn), and (yn) are defined as follow:

    [tex]x_{n + 1} = \frac{x_n + y_n}{2}, n \in \mathbb{N}[/tex] (1)
    [tex]y_{n + 1} = \sqrt{x_n y_n}, n \in \mathbb{N}[/tex] (2)

    Now find the limit of xn, and yn (Or does it tell you to prove that the limit of the two sequences are the same?).

    Is that the correct problem?


    Ok, now you must at least have a vision of how xn, and yn behave. Draw a pictures like this:


    Now, we have: x1 = (x0 + y0) / 2, that means, x1 lies exactly at the middle of x0, and y0.

    [tex]y_1 = \sqrt{x_0 y_0} > \sqrt{y_0 ^ 2} = y_0[/tex]

    You'll also have: [tex]x_1 - y_1 = \frac{x_0 - 2\sqrt{x_0 y_0} + y_0}{2} = \frac{(\sqrt{x_0} - \sqrt{y_0}) ^ 2}{2} > 0[/tex], so x1 > y1.


    Now, where do x2, and y2 lie?


    So, in conclusion, let's answer some questions:

    1. xn, and yn, which is greater?

    2. Is (xn) an increase sequence, or a decrease sequence? Can you prove it?

    3. Is (yn) an increase sequence, or a decrease sequence? Can you prove it?

    4. Are they bounded? Do they have limit?

    5. Do they both have the same limit?

    Ok, I think you can take it from here. Can you? :)
    Last edited: Nov 26, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Sequence and Series, finding relationship
  1. Series and sequences (Replies: 4)

  2. Sequence and series (Replies: 3)

  3. Series and sequences (Replies: 3)

  4. Sequences and series (Replies: 2)

  5. Sequences and Series (Replies: 25)