Is {yn} a Cauchy Sequence if {xn} Is?

Click For Summary
SUMMARY

The discussion centers on proving that if {xn} is a Cauchy sequence and for every η>0 there exists a positive integer N such that for all n>N, |xn-yn|<η, then {yn} is also a Cauchy sequence. The proof strategy involves demonstrating that for every ε>0, there exists a positive integer N such that for all n, m>N, |yn-ym|<ε. The triangle inequality plays a crucial role in transitioning from |xn-yn| to |yn-ym|, allowing the conclusion that {yn} inherits the Cauchy property from {xn}.

PREREQUISITES
  • Cauchy sequences in real analysis
  • Understanding of the triangle inequality
  • Basic knowledge of limits and convergence
  • Familiarity with ε-δ definitions in analysis
NEXT STEPS
  • Study the properties of Cauchy sequences in detail
  • Learn about the triangle inequality and its applications in proofs
  • Explore the implications of Cauchy sequences on convergence in real analysis
  • Investigate other types of sequences and their convergence criteria
USEFUL FOR

Mathematics students, particularly those studying real analysis, educators teaching sequence convergence, and anyone interested in the foundational concepts of Cauchy sequences.

bloynoys
Messages
25
Reaction score
0

Homework Statement



Prove the following assertion: Suppose {xn} and {yn} are Cauchy sequences of real number. If {xn} is a cauchy sequence and for every η>0 there exists a pos. int. N such that for every n>N so that abs(xn-yn)<η then {yn} is a Cauchy sequence.


Homework Equations


None



The Attempt at a Solution


We will prove that {yn} is a cauchy sequence by showing that for every ε>0 there exists a pos. int. N so that both n and m >N so that abs(yn-ym)<ε.

Consider ε>0 arbitrary.
Since {xn} is a cauchy sequence and by hypothesis for every η>0 there exists an N so that every n>N abs(xn-yn)<η. Choose such an N.
Consider n,m>N arbitrary.

Then I know I need to get from abs(yn-ym) to ε but unsure how to use what I have to get there correctly and if I have the rest of the proof right.
 
Physics news on Phys.org
bloynoys said:

Homework Statement



Prove the following assertion: Suppose {xn} and {yn} are Cauchy sequences of real number. If {xn} is a cauchy sequence and for every η>0 there exists a pos. int. N such that for every n>N so that abs(xn-yn)<η then {yn} is a Cauchy sequence.


Homework Equations


None



The Attempt at a Solution


We will prove that {yn} is a cauchy sequence by showing that for every ε>0 there exists a pos. int. N so that both n and m >N so that abs(yn-ym)<ε.

Consider ε>0 arbitrary.
Since {xn} is a cauchy sequence and by hypothesis for every η>0 there exists an N so that every n>N abs(xn-yn)<η. Choose such an N.
Consider n,m>N arbitrary.

Then I know I need to get from abs(yn-ym) to ε but unsure how to use what I have to get there correctly and if I have the rest of the proof right.

Use the Cauchy sequence {xn} as your bridge, think about triangle inequality, also note that η may be set according to ε
 

Similar threads

Replies
1
Views
7K
Replies
6
Views
7K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
1
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
6K