Series and Parallel Combination

[marcoforce]

[Note: Thread has been moved to the homework forums by a mentor]

This is the Given problem

This is my solution part 1
- What I did here is I series the R3 and R4 (R3 + R4), and I parallel the R34 to R5 (most of the calculation are from the calculator)

This is my solution part 2

The problem is when I check and compute the total voltage from V1,V2,V3,V4,V5 the result is 12 and more volts not 8 volts exactly, I can't locate my error and miscalculation

 

[SteamKing]

[Note: Thread has been moved to the homework forums by a mentor]

This is the Given problem
View attachment 100290
This is my solution part 1
- What I did here is I series the R3 and R4 (R3 + R4), and I parallel the R34 to R5 (most of the calculation are from the calculator)
View attachment 100292

This is my solution part 2

View attachment 100293

The problem is when I check and compute the total voltage from V1,V2,V3,V4,V5 the result is 12 and more volts not 8 volts exactly, I can't locate my error and miscalculation

The problem comes when you check the voltage drops in the parallel resistor section. In the parallel resistors, the current of 1.075A divides, so there is a different current in each branch. The same voltage drop, however, is present in each branch.

For this circuit, I₅ ⋅ 10 Ω = I₃₄ ⋅ (3 Ω + 5 Ω), and I₃₄ + I₅ = 1.075 A

 

[marcoforce]

The problem comes when you check the voltage drops in the parallel resistor section. In the parallel resistors, the current of 1.075A divides, so there is a different current in each branch. The same voltage drop, however, is present in each branch.

For this circuit, I₅ ⋅ 10 Ω = I₃₄ ⋅ (3 Ω + 5 Ω), and I₃₄ + I₅ = 1.075 A

Yes, The current in I₃ and I₄ is different to I₅, since I₃₄ is parallel to I₅ their voltage is the same. Sorry I still don't get it, maybe I'm missing something. My circuit in I₃ and I₄ is .60 and in I₅ is .477 so to add = 1.077A which is close.

 

[SteamKing]

Yes, The current in I₃ and I₄ is different to I₅, since I₃₄ is parallel to I₅ their voltage is the same. Sorry I still don't get it, maybe I'm missing something. My circuit in I₃ and I₄ is .60 and in I₅ is .477 so to add = 1.077A which is close.

In your original voltage check, you are adding the voltage drop from both branches of the parallel resistors. The voltage drop in each branch is the same; you only need to add this voltage drop once to the drops in R1 and R2.

 

[marcoforce]

In your original voltage check, you are adding the voltage drop from both branches of the parallel resistors. The voltage drop in each branch is the same; you only need to add this voltage drop once to the drops in R1 and R2.

Sorry, But I still don't get it, what must be the V5, V3 and V4 should be?

 

[SteamKing]

Sorry, But I still don't get it, what must be the V5, V3 and V4 should be?

V5 = I5 ⋅ 10Ω

I think you can work out what V3 and V4 are.

The point is in your original voltage drop calculations around the circuit, you counted the voltage drop in each branch of the parallel resistors separately, which is why you got a total voltage drop of more than 8 volts. You only need to count the voltage drop in one branch of the parallel resistors, either V5 or V3 + V4, when checking that the voltage drop in the circuit balances the voltage from the battery.

 

[marcoforce]

V5 = I5 ⋅ 10Ω

I think you can work out what V3 and V4 are.

The point is in your original voltage drop calculations around the circuit, you counted the voltage drop in each branch of the parallel resistors separately, which is why you got a total voltage drop of more than 8 volts. You only need to count the voltage drop in one branch of the parallel resistors, either V5 or V3 + V4, when checking that the voltage drop in the circuit balances the voltage from the battery.

Meaning Vtotal = V1 + V2 + V3 + V4 OR V1 + V2 + V5?

 

[SteamKing]

Meaning Vtotal = V1 + V2 + V3 + V4 OR V1 + V2 + V5?

Exactly.

 

[marcoforce]

Thanks! Now I remembered.