Series expansion of logarithmic function

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To find the first three non-zero terms in the series expansion of ln(5+p) for small values of p, it is suggested to rewrite the function as ln(5[1+(p/5)]). This allows the use of logarithmic properties to separate the terms. The series expansion can then be applied to the term ln(1+(p/5)), which is suitable for small p. The accuracy of the expansion diminishes as p moves away from -4, but the focus remains on deriving the first three non-zero terms. The approach emphasizes the importance of correctly applying logarithmic identities for effective expansion.
seboastien
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Homework Statement


Find first three non zero terms in series expansion where the argument of funstion is small

ln(5+p)

Homework Equations





The Attempt at a Solution



The only way I could think how to do this is by saying ln(5+p) = ln(1+(4+p)) and expanding to

(4+p)- 1/2(4+p)^2 + 1/3(4+p)^3 - ... however, I imagine that this would only work if p was approx -4.
 
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Come on guys! I really need to know how to do this!
 
seboastien said:

Homework Statement


Find first three non zero terms in series expansion where the argument of funstion is small

ln(5+p)

Homework Equations





The Attempt at a Solution



The only way I could think how to do this is by saying ln(5+p) = ln(1+(4+p)) and expanding to

(4+p)- 1/2(4+p)^2 + 1/3(4+p)^3 - ... however, I imagine that this would only work if p was approx -4.
Well, the accuracy, for any finite polynomial expansion, deteriorates as p gets farther from -4 but is the accuracy really relevant? You are only asked to "Find first three non zero terms".
 
How do I find the first three non-zero terms of ln(5+p), I'm pretty sure that my answer is wrong.
 
You'll want to write this as ln( 5 [ 1+(p/5) ] ) ; then use the properties of logarithms to write it as two terms, one of which is the term you would do the series expansion for.
 
Thank you
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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