Set Theory/Compactness Question

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SUMMARY

The discussion revolves around a problem in set theory and topology involving compact subsets K and L within topological spaces X and Y. The user has established that for each point x in K, there exist open sets Ux and Vx such that K x L is contained in Ux x Vx, which is a subset of an open set W in X x Y. The challenge lies in demonstrating the existence of open sets U and V such that K x L is contained in U x V, while also ensuring U x V is a subset of W. The key insight is that a finite intersection of open sets is open, which can be leveraged to solve the problem.

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Homework Statement


This is part of a question I've managed to do most of.. I've got as far as:

Let K, L be compact subsets of topological spaces X,Y respectively, and let K x L \subseteq W where W is open in X x Y.

I have already shown that: for each x in K there exist sets Ux, Vx, open in X,Y respectively such that x\inUx, L\subseteq Vx and Ux x Vx \subseteq W.

Now I have to show there exist sets U, V open in X,Y respectively and such that K x L \subseteq U x V \subseteq W.

Homework Equations


I'm pretty stuck- If I set U as the union of Ux over x in X, and V as the union of Vx over x in X, I obviously get that K x L \subseteq U x V, but I don't think this in necessarily contained in W. Alternatively if I take a union of (Ux x Vx) over x in X then this IS contained in W but can't be written in the form U x V (I don't think). I also haven't yet used the compactness property- this must be relevant but not really sure where..

I also considered taking V as the intersection of the Vx over x but this isn't necessarily open.

Any clues welcome! I have mock exams soon, need to get my head around this stuff :/

Thanks
 
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The idea is indeed to take the intersection of the V_x, but this isn't open: an arbitrary intersection of open sets isn't necessarily open. BUT a finite intersection of open sets IS open. So we must reduce this collection to a finite collection somehow.

To do this, notice that \{U_x~\vert~x\in K\} is an open cover of K.
 

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