Setting up limits of integration for multiple integral

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dustbin
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Homework Statement



I need to find the volume of the region bounded by

[tex](x-1)^2 + y^2 =1 \ \ \text{and} \ \ x^2+y^2+z^2=4 \ .[/tex]
But I only need help setting up the limits of integration.

Homework Equations



The typical cylindrical change of variables.

The Attempt at a Solution



I have [itex]0 \leq r \leq 2\cos\theta, \ -\sqrt{4-r^2} \leq z \leq \sqrt{4-r^2}, \ \text{and} \ -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}.[/itex] Then the volume is given by
[tex] \int\limits_{-\pi/2}^{\pi/2}\int\limits_0^{(2\cos\theta)}\int\limits_{(-\sqrt{4-r^2})}^{(\sqrt{4-r^2})} dz\,(r\,dr)\,d\theta \ .[/tex]
 
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@haruspex: Sorry, but I do not know what you mean by cylindrical coordinate frame.

@HallsofIvy: I thought that taking [itex]0 \leq r \leq 2\cos\theta[/itex] with [itex]\theta\in(-\pi/2, \pi/2)[/itex] made it so that I would be integrating over the projection of the cylinder onto the [itex]x,y[/itex] plane as a circle of radius 1 centered at (1,0). The region is bound by [itex]\pm\sqrt{4-r^2}[/itex] on [itex]z[/itex]. Can I get some insight into how I can fix my limits of integration?
 
dustbin said:

Homework Statement



I need to find the volume of the region bounded by

[tex](x-1)^2 + y^2 =1 \ \ \text{and} \ \ x^2+y^2+z^2=4 \ .[/tex]
But I only need help setting up the limits of integration.

Homework Equations



The typical cylindrical change of variables.

The Attempt at a Solution



I have [itex]0 \leq r \leq 2\cos\theta, \ -\sqrt{4-r^2} \leq z \leq \sqrt{4-r^2}, \ \text{and} \ -\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}.[/itex] Then the volume is given by
[tex] \int\limits_{-\pi/2}^{\pi/2}\int\limits_0^{(2\cos\theta)}\int\limits_{(-\sqrt{4-r^2})}^{(\sqrt{4-r^2})} dz\,(r\,dr)\,d\theta \ .[/tex]
That integral looks fine to me.

What's your question?