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Any help?

- Thread starter TheBigK1d
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- #1

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Any help?

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- #3

DaveC426913

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It is the least dense of all the planets - less dense than water - and its day is less than 11 hours.

Its equatorial circumference is about 10% larger than its polar circumference.

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A.T.

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You have to add the potential of gravity and centrifugal force. The shape of the planet is a surface of constant combined potential.I haven't taken calculus yet and don't really know how to calculate what its shape might be.

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Sure, but that's a hard problem. The gravitational potential depends, in turn, on the shape.You have to add the potential of gravity and centrifugal force. The shape of the planet is a surface of constant combined potential.

http://seismo.berkeley.edu/~rallen/eps122/lectures/L16.pdf gives the strength of gravity at latitude λ as g

http://en.wikipedia.org/wiki/Equatorial_bulge#Mathematical_expression provides an expression as a function of spin, but says the formula is only valid for small deviations from the spherical.

- #6

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The polar axis must be at least 56% of the equatorial diameter. After that the planet would be nonaxisymmetric. I don't know what would happen then, but it wouldn't be good.

Any help?

- #7

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Thanks for the help - I'll check out the book you mentioned

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