Shape of graph of torque vs angular displacement of galvanometer

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SUMMARY

The relationship between torque and angular displacement in a galvanometer is linear, as established by the formula τ = kθ, where τ represents torque, k is the spring constant, and θ is the angular displacement. When the current is switched off, the needle returns to its original position due to the restoring torque provided by the spring, confirming that deflection is directly related to torque. The maximum torque occurs at the maximum angular displacement, θ0, while zero torque corresponds to zero deflection. This relationship is independent of the current or magnetic field, as the torque can be generated by manual twisting of the coil.

PREREQUISITES
  • Understanding of torque and angular displacement concepts
  • Familiarity with the formula τ = kθ for restoring torque
  • Basic knowledge of galvanometer operation
  • Concept of spring constant (k) in mechanical systems
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  • Explore the dynamics of galvanometers and their applications
  • Learn about the role of restoring torque in oscillatory systems
  • Investigate the effects of varying spring constants on deflection
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songoku
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Homework Statement
The diagram below shows galvanometer. A coil of wire is wound around a circular iron core which is placed between two magnets with circular surface such that the magnetic field (indicated by arrows) on the surface of iron core is directed perpendicularly onto the surface and of the same magnitude across the surface of iron core as shown in diagram.

When a constant current flows in the coil, the needle will be deflected to angle ##\theta## from the vertical direction. Sketch a graph to show the variation of torque ##\tau## on the soft iron core due to magnetic force acting on the coil with the angular displacement ##\theta## of the needle as the needle rotates from zero to ##\theta_0##. Explain
Relevant Equations
##\tau## = F . d
1616641905783.png


I know the torque will be zero when the deflection is zero and will be maximum when the angular displacement is θ0 but how to determine the exact shape of the graph?

Thanks
 
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The question asks for the relationship between the torque and the deflection. Note that this has nothing to do with the current or the magnets. You could throw those away and twist the coil by hand and get the same result.
So what does control the relationship?
 
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haruspex said:
The question asks for the relationship between the torque and the deflection. Note that this has nothing to do with the current or the magnets.
I thought the value of torque acting on the needle is somewhat related to current flowing through the galvanometer, maybe something like F = BIL and τ = F.d so the magnitude of current also affects the deflection.

If torque has nothing to do with current of magnetic field, how can torque on the needle produced?

You could throw those away and twist the coil by hand and get the same result. So what does control the relationship?
Maybe magnitude of force applied by hand?

Thanks
 
songoku said:
I thought the value of torque acting on the needle is somewhat related to current flowing through the galvanometer, maybe something like F = BIL and τ = F.d so the magnitude of current also affects the deflection.

If torque has nothing to do with current of magnetic field, how can torque on the needle produced?Maybe magnitude of force applied by hand?

Thanks
The current creates the torque, and the torque creates the deflection. A given value of torque, no matter how provided, results in a certain deflection.
What determines how much deflection results from a given torque?
Hint: if the current is switched off what happens to the needle? Why does that happen?
 
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haruspex said:
The current creates the torque, and the torque creates the deflection. A given value of torque, no matter how provided, results in a certain deflection.
What determines how much deflection results from a given torque?
Hint: if the current is switched off what happens to the needle? Why does that happen?
If the current is switched off, the needle will return to original position because there is restoring torque from spring. So it means that the deflection will be related to torque by spring.

Formula of restoring torque is: ##\tau = k.\theta## so the shape of the graph will be linear line similar to y = mx + c.

Am I correct? Thanks
 
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songoku said:
If the current is switched off, the needle will return to original position because there is restoring torque from spring. So it means that the deflection will be related to torque by spring.

Formula of restoring torque is: ##\tau = k.\theta## so the shape of the graph will be linear line similar to y = mx + c.

Am I correct? Thanks
Yes.
 
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Thank you very much haruspex
 

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