Shear stress on a bar with a bend

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SUMMARY

The discussion focuses on calculating the shear stress (\tauxy) at point A on a solid round bar that is fixed at one end and bends 90 degrees. The relevant equations used are the torsion formula (\tau = Tc/J) and the beam shear formula (\tau = VQ/It). The user provided specific values for forces and dimensions, resulting in a calculated torsion shear of -16900 psi and a beam shear of -2844 psi. The total shear stress was computed as the difference between these two values.

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  • Understanding of shear stress calculations in mechanics
  • Familiarity with torsion and beam shear equations
  • Knowledge of material properties and cross-sectional geometry
  • Ability to apply Cartesian coordinates in force analysis
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  • Review the derivation and application of the torsion formula in Mechanics of Materials
  • Study beam shear calculations and the significance of the centroid in cross-sectional analysis
  • Explore examples of shear stress in bent beams and fixed supports
  • Investigate online resources or textbooks that provide detailed explanations of shear stress problems
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Homework Statement



I have encountered this problem several times in class, but have never really understood it. There is a solid round bar that is fixed on one end, and that bends 90 degrees a ways down. At the free end of the bar there are forces applied in each Cartesian direction.
Like this: http://farm4.static.flickr.com/3448/4559398860_d6c6e250a0_o.jpg"

The question is to determine the shear stress \tauxy at point A (on the outer edge of the tube, radially parallel to the z-axis).

Homework Equations



Torsion - \tau = Tc/J
Beam - \tau = VQ/It

The Attempt at a Solution



I plug in my values in the above equations, and add them up depending on the shear direction, but I don't seem to get the right answer.

I'm hoping someone can help me with the general idea for this type of problem or point me to a website that explains it clearly.

Thanks!
 
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What values are you using for the torque and the shear force?
 
Here is what I tried:

Fx=500lbf
Fy=-800lbf
T=Fy14in
c=r (radius)
J=pi*r4/4


which gives torsion shear=-16900psi

V=Fy
Q=y'A'
y'=r
A'=pi*r2/2
t=r

with beam shear=-2844psi

total shear (xy)=torsion shear-beam shear

It's been a while since I was actually in Mechanics of Materials, so that might be way wrong though :).
 
It's been a while for me too, but isn't y' the distance to the centroid of the top or bottom half of the cross section?
 
ah, yes you are right. Unfortunately I don't have the correct answer in front of me anymore so I can't check if that's all that is wrong.

Hopefully the other stuff looks right though?
 
Yep, the torsion part looks good.
 

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