Shear Stress over Stationary Plate

[lfwake2wake]

1. A large plate moves with speed (v.o) over a stationary plate on a layer of oil of thickness (d) and viscosity (u). If the velocity profile is that of a parabola, with the oil at the plates having the same velocity as the plates, what is the shear stress on the moving plate from the oil? If a linear profile is assumed, what is the shear stress on the moving plate? (Answers: u*v.o/(2d) and u*v.o/d)

Homework Equations

t: shear stress
t=u*(dv)/(dy)
v=md^2+c

The Attempt at a Solution

So I have the answer, but I cannot figure out the solution. If the velocity changes parabolically, then you have the equation v=md^2+c. dv=2md. So when d=0, v=0 and t=u*(2md-0)/(d-0). This is my solution, but obviously is not correct with the above answers. Any help would be greatly appreciated.
Thanks

 

[Chestermiller]

There is not information provided to solve for the case of a parabolic profile. For the linear profile, the velocity gradient is $v_0/d$ and the shear stress is uniform at $\mu\frac{v_0}{d}$