I'm confused when to use the shell method vs. the disk method(adsbygoogle = window.adsbygoogle || []).push({});

Specifically in this problem:

If the region encolsed by the y-axis, the line y=2 and the curve y=[tex]\sqrt{x}[/tex] is revolved around the y-axis, the volume of the solid generated is:

However when I use the shell method and the disk method I get different answers

Can someone tell me what I'm doing wrong?

Disk Method:

[tex]\pi[/tex] [tex]\int[/tex]y^4 dy evaluated from 0 to 2

Shell Method:

2[tex]\pi[/tex][tex]\int[/tex]x(2-[tex]\sqrt{x}[/tex])dx

Help please!!

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# Homework Help: Shell method versus disk method

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