Show that if X is a bounded random variable, then E(X) exists.

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Homework Statement



Show that if X is a bounded random variable, then E(X) exists.

Homework Equations


The Attempt at a Solution



I am having trouble of finding out where to begin this proof.This is what I got so far:

Suppose X is bounded. Then there exists two numbers a and b such that P(X > b) = 0 and P(X < a) = 0 and P(a <= X <= b) = 1.
I have no idea if I am even doing this right. Anyone wanting to take a crack at this one? Thanks.
 
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How do your course materials define a "bounded random variable"? The claim "if X is a bounded random variable, then E(X) exists" isn't true using the usual definition of a "bounded random variable".

Perhaps your problem assumes the domain of X is bounded as well as the range.
 
Stephen Tashi said:
How do your course materials define a "bounded random variable"? The claim "if X is a bounded random variable, then E(X) exists" isn't true using the usual definition of a "bounded random variable".

Perhaps your problem assumes the domain of X is bounded as well as the range.

The book specifically defined X as bounded as the following:

|X| < M < ∞ . Here is the whole question, word for word:

Show that if a random variable is bounded—that is, |X| < M < ∞—then
E(X) exists.I do not know about the range though.
 
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number0 said:
The book specifically defined X as bounded as the following:

|X| < M < ∞ .

I do not know about the range though.

I see what the book is doing now. I was thinking of a probability density function being "bounded" as meaning it is a function with a bounded range on a possibly infinite domain. Your book means the domain is bounded and you probably get to assume the range of the function is [0,1] or a subset of it. So you can bound the integral of the expression x f(x) by (M)(1) = M.

Have you studied theorems that say something to the effect that bounded (in range) continuous function on a closed interval is integrable?
 
start witha a well-behaved continously distributed random variable (no delta functions)

then start with the definition of E(X) in integral form.

You know integral of the distribution function p(x) converges, so can you show the integrand in the expectation is always less than something you know converges eg. xp(x) < c, or xp(x) < cp(x) for all x?