Show that sometimes the acceleration is exactly 120mi/h^2

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The discussion revolves around demonstrating that a car's acceleration reaches exactly 120 mi/h² between 2:00 PM and 2:10 PM, given its speed changes from 30 mph to 50 mph. Utilizing the Mean Value Theorem, the average acceleration is calculated as 20 mph over 10 minutes, which translates to 120 mph over one hour. The conversation also clarifies the notation of acceleration in LaTeX, emphasizing that acceleration is expressed in distance per time squared, confirming that 120 mi/h² is a valid representation of acceleration.

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karush
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At $$ 2:00\text{ pm}$$ a car’s speedometer reads $$30\text { mph}$$.
At $$2:10$$ it reads $$50 \text { mph}$$.
Show that at some time between $$2:00$$ and $$2:10$$
the acceleration is exactly $$120\text{ mi} / h^2$$

This is in section of the Mean Value Theorem so since
$$
f'(c)=\frac{f(b)-f(a)}{b-a}
\Rightarrow
\frac{50-30}{10-0}
$$

I don't see that $120 mi/ h^2$ is going to fit into this also why is there $h^2$





 
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20 mph in 10 minutes is exactly 120 mph in an hour.

The letter "h" should be in an upright font, just like "mi" and "mph" because it is not the name of a variable that has a numerical value (like $x$), but a contraction for "hour".
 
if you look at "h" in the text commands it shows an upright "h"
the slash may of changed it
I was wondering tho why there is an $h^2$

the latex seem to want to change the h to italics
 
karush said:
I was wondering tho why there is an $h^2$
As opposed to what: h, s (for seconds), s² or something else?

karush said:
the latex seem to want to change the h to italics
LaTeX makes characters in math mode italic. To make them upright, use \text{} or \mathrm{}. Of course, this distinction between upright/italic is not really important.
 
Evgeny.Makarov said:
As opposed to what: h, s (for seconds), s² or something else?

LaTeX makes characters in math mode italic. To make them upright, use \text{} or \mathrm{}. Of course, this distinction between upright/italic is not really important.

ok h^2 in latex is $h^2$

\text {h}^2 in latex $\text {h}^2$

I can see that we get

$$\frac{120 \text{ mi}}{\text{h}}$$

but what is

$$\frac{120 \text{ mi}}{\text{h}^2}$$
 
If you changed your location, you would have a change of 120 miles over the course of 1 hour: 120 mi/h, or 120 mph. As it is, you are hanging speed, which itself is measured in mph. Thus, you changed 120 mph in 1 hour, or $\dfrac{120\,\mathrm{mi/h}}{\mathrm{h}}$, or $\dfrac{120\,\mathrm{mi}} {\mathrm{h}^2}$.

All acceleration is measured in distance per time squared, whether it's m/s² or mi/h².
 
ok, that makes sense...

they didn't have any examples of this type of exercise.:cool:
 

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