Show that the probability of scroing exactly n points is

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SUMMARY

The probability of scoring exactly n points when tossing a coin repeatedly, where heads scores one point and tails scores two points, is given by the formula (2 + (-1/2)^n) / 3. This conclusion is derived from analyzing the scoring mechanism and the conditions under which the game continues until the score meets or exceeds n. The discussion emphasizes using mathematical induction to prove this probability formula, starting with initial cases for n=1 and n=2 and then establishing the inductive step.

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  • Understanding of probability theory
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  • Basic knowledge of coin tossing games
  • Ability to manipulate algebraic expressions
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Homework Statement


A player tosses a coin repeatedly. Heads is one point, tails is two points. A player tosses until his score equals or exceeds n. Show that the probability of scoring exactly n points is (2+(-1/2)^n)/3


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The Attempt at a Solution


My guess would be a proof by induction, but not really sure how to go about this or any attempted proof

Thanks
 
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Seems pretty straightforward to me. Why don't you start by doing the initial cases (n=1,2) and writing out the inductive step?
 

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