Showing a random Variable has a continuous uniform distribution

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SUMMARY

The discussion focuses on demonstrating that the variable Z, defined as Z=(b-a)(x-θ)+(1/2)(a+b), has a continuous uniform distribution over the interval (a,b). It is established that if y=x-θ is uniformly distributed over the interval (-1/2, 1/2), then Z, being a linear transformation of y, is also uniformly distributed. The endpoints of Z are derived from the endpoints of y, confirming that Z takes values from a to b.

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f(x)=1, θ-1/2 ≤ x ≤ θ+1/2

Given that Z=(b-a)(x-θ)+(1/2)(a+b) how would you show that Z has a continuous uniform distribution over the interval (a,b)?
Any help would be much appreciated.
 
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Let y = x-θ. Then y is uniform over the interval (-1/2,1/2). Since Z is linear in y, it is also uniformly distributed.
Put in the endpoints of y to get the endpoints for the Z interval. At y = -1/2, Z = a, while at y = 1/2, Z = b.

If you want to do a little work, start with P(Z < z) and transform it into P(Y < y) or P(X < x).
 
Ohh yeah that makes a ton of sense. Idk what I was thinking. Thanks!
 

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