Showing the temperature distribution in an infinitely long cylinder

Click For Summary
SUMMARY

The temperature distribution in an infinitely long cylinder with insulated sides and an initial temperature distribution defined by u(x, 0) = 0 for |x| < L and u0 for |x| > L is given by the formula u(x, t) = (1/2)u0[2 - erf((x + L)/(√4c2t)) + erf((x - L)/(√4c2t))] for t > 0. The relevant equation for the temperature distribution is u(x, t) = (1/√4πc2t)∫e^(-(x - y)²/4c²t) f(y) dy, where the bounds of integration are from -∞ to ∞. The discussion highlights the need for a change of variables to solve the integral but emphasizes the challenge of determining new bounds after this transformation.

PREREQUISITES
  • Understanding of heat conduction principles in one-dimensional systems
  • Familiarity with the error function (erf) and its applications
  • Knowledge of integral calculus, particularly improper integrals
  • Basic concepts of partial differential equations (PDEs)
NEXT STEPS
  • Study the properties and applications of the error function (erf)
  • Learn about change of variables in integrals and how to determine new bounds
  • Explore the heat equation and its solutions in various geometries
  • Investigate numerical methods for solving PDEs, particularly for heat conduction problems
USEFUL FOR

Students and professionals in physics and engineering, particularly those focused on thermal analysis and heat transfer in cylindrical geometries.

Rubik
Messages
95
Reaction score
0

Homework Statement


Show that the temperature distribution in an infinitely long cylinder of metal with insulated sides and initial distribution

u(x, 0) = 0, the absolute value of x < L
u0, the absolute value of x > L

where u0 is a constant, is given for t >0, by

u(x, t) = (1/2)u0[2 - erf((x +L)/(√4c2t)) + erf((x - L)/(√4c2t))


Homework Equations




u(x, t) = 1/√4∏c2t∫e-(x - y)2/4c2t f(y) dy bounds = -∞<x<∞

The Attempt at a Solution



= (u0/√4∏c2t)∫e-(x - y)24c2tdy

Then I know you make a change of variables but I am having trouble with finding my new bounds of integration after I make the change of variables?
 
Physics news on Phys.org
relevant equation*

u(x, t) = (1/√4c2t)∫e-(x - y)2/4c2tf(y) dy

Attempt at a solution*

= u0/√4∏c2t)∫e-(x - y)2/4c2tdy

Then I know I need to make a change of variables but after I do that I am not sure how to determine the new bounds of integration?
 

Similar threads

Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
Replies
14
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K