Sign of potential energy of SHO

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SUMMARY

The discussion centers on the calculation of potential energy (U) in simple harmonic oscillators (SHO) using the work-energy principle. The potential energy is derived from the work done on a spring, expressed as U = (1/2)kx² when the spring is stretched. Participants clarify that while the change in potential energy (dU) is positive when moving away from the mean position and negative when moving towards it, the potential energy itself remains positive or zero. The confusion arises from the interpretation of work done by the spring versus work done by an external agent.

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  • Understanding of simple harmonic motion (SHO)
  • Familiarity with potential energy and work-energy principles
  • Knowledge of calculus for integration of force over displacement
  • Concept of conservative forces and their relation to potential energy
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Students of physics, particularly those studying mechanics and oscillatory motion, as well as educators looking to clarify concepts related to potential energy in simple harmonic oscillators.

  • #31
OP remains as convinced as ever that the HO potential changes sign, and is now asserting that there is some sort of global physicist conspiracy to ignore this inconvenient "fact". Please see:

https://www.physicsforums.com/showthread.php?t=730150
 
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  • #32
devang2 said:
Thanks a lot for the answer . No one has pointed so for where i have gone wrong if i use basic formula dU =-W to calculate potential energy and use dot product to calculate work . This method leads to positive and negative signs when the particle moves away and toward the mean position respectively
That equation is incorrect - where did you get it from?
The correct relation is dW=-dU or dU=dW - depending on the context - as explained to you in post #5.
More precisely: http://en.wikipedia.org/wiki/Potential_energy#Work_and_potential_energy
... but it is not the definition.

One of the upshots of that equation is that there is no absolute zero for potential energy.
When we talk about a particular value of potential, we are using a shorthand for the difference in potential between two places.

There are conventions for some situations for where we put that zero by default.
For instance, for gravity, close to the Earth's surface, we put U=0 on the ground.
In that case you will see that U<0 below the ground, and U>0 above the ground.

If you start below the ground, and move upwards, then v>0, dU>0, and U goes from negative values to positive values.

But if we are talking about gravity at a long distance, it is more convenient to put U=0 at an infinite distance away. In that case, U<0 everywhere.

If you move towards a mass, dU<0, but U<0
If you stay still, or execute a circular orbit dU=0 but U<0
If you move away from the mass dU>0 but U<0

For a mass on a spring, it is convenient to put U=0 at the center of the motion simply because U increases to either side. This makes U>0 everywhere for the mass.
If the mass moves towards the center, then dU<0 and U>0
If the mass moves away from the center, then dU>0 and U>0
 
  • #33
Given the OP's history on this topic, there is no reason to continue either of these threads.
 

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