MHB Simple algebra solve (1-x)(1-0.03)^2 = 0.667

  • Thread starter Thread starter bzsmtp
  • Start date Start date
  • Tags Tags
    Algebra
Click For Summary
The discussion revolves around solving the equation (1-x)(1-0.03)^2 = 0.667, which is part of a poker book's probability analysis. Initially, the user struggled to reach the answer of x = 0.291. After some confusion, they realized that rearranging the equation allows them to isolate x, leading to the correct calculation. The solution involves understanding that (1-x) can be expressed as 0.667 divided by (1-0.03)^2. Ultimately, the user successfully solved the problem and expressed gratitude for the assistance.
bzsmtp
Messages
2
Reaction score
0
I am following a book and can't arrive at the same answer. Not sure what to try next.

(1-x)(1-0.03)^2

the book then says = 0.667
x= 0.291

my attempt
(1-x)(1 - .03)(1 - .03)

then i get confused
(1-x)(0.9409)

not sure ><
 
Mathematics news on Phys.org
Hello, and welcome to MHB! (Wave)

Can you post the original problem in its entirety?
 
MarkFL said:
Hello, and welcome to MHB! (Wave)

Can you post the original problem in its entirety?

its a poker book. it says
x is the probability that the original raiser defends, and 1-0.03 is the probability that each blind folds.

then just writes

(1-x)(1-0.03)^2 = 0.667 therefore x = 0.291

- - - Updated - - -

ooooooo i get it

(1-x)(1-0.03)^2 = 0.667 means (1-x)=0.667/(1-0.03)^2=0.667/0.97^2=0.7089 so x=1-0.70289=0.2911

can delete thread now thank you
 
Glad you got it squared away. :)
 
MarkFL said:
Glad you got it squared away. :)
Don't you be no square...:)
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
View full post »

Similar threads

B What went wrong with (-x)^2=x^2?
  • · Replies 22 ·
Replies
22
Views
2K
MHB Solve $2\cos^2(x)=1$: Find $\theta$
  • · Replies 7 ·
Replies
7
Views
2K
MHB Solving Trig Identity: Sin[1/2 sin^−1 (x)] = 1/2 X (sqr(1+x) –sqr(1-x))
  • · Replies 2 ·
Replies
2
Views
1K
I Is arcsec = 1 divided by arccos ? Arcsec = 1/arccos
  • · Replies 34 ·
2
Replies
34
Views
4K
MHB Solve $(x^2-7x+11)^{x^2-13x+42}=1$ Equation
  • · Replies 7 ·
Replies
7
Views
1K
MHB Equation 2: Prove that ##x^2+2x\sqrt x+3x+2\sqrt x+1=0##
  • · Replies 4 ·
Replies
4
Views
1K
MHB Solve the Floor Value of x in $x^2+1=2x$
  • · Replies 3 ·
Replies
3
Views
1K
B The Paradox of 1 – 1 + 1 – 1 + 1 – 1 + …
  • · Replies 5 ·
Replies
5
Views
2K
MHB Solve Floor Equation 7: x^2=2x-1
  • · Replies 2 ·
Replies
2
Views
2K
MHB Solve Equation: $\sqrt{1+\sqrt{1-x^2}}$
  • · Replies 3 ·
Replies
3
Views
1K