Simple algebra solve (1-x)(1-0.03)^2 = 0.667

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SUMMARY

The discussion revolves around solving the algebraic equation (1-x)(1-0.03)^2 = 0.667, where x represents the probability that the original raiser defends in a poker scenario. The correct solution is derived as x = 0.291. The user initially struggled with the calculation but clarified that (1-x) can be expressed as 0.667 divided by (1-0.03)^2, leading to the final value of x.

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I am following a book and can't arrive at the same answer. Not sure what to try next.

(1-x)(1-0.03)^2

the book then says = 0.667
x= 0.291

my attempt
(1-x)(1 - .03)(1 - .03)

then i get confused
(1-x)(0.9409)

not sure ><
 
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Hello, and welcome to MHB! (Wave)

Can you post the original problem in its entirety?
 
MarkFL said:
Hello, and welcome to MHB! (Wave)

Can you post the original problem in its entirety?

its a poker book. it says
x is the probability that the original raiser defends, and 1-0.03 is the probability that each blind folds.

then just writes

(1-x)(1-0.03)^2 = 0.667 therefore x = 0.291

- - - Updated - - -

ooooooo i get it

(1-x)(1-0.03)^2 = 0.667 means (1-x)=0.667/(1-0.03)^2=0.667/0.97^2=0.7089 so x=1-0.70289=0.2911

can delete thread now thank you
 
Glad you got it squared away. :)
 
MarkFL said:
Glad you got it squared away. :)
Don't you be no square...:)
 

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