- #1
Gamerex
- 25
- 0
I came across this when doing another problem:
Suppose we have 2 numbers, (a+b) and (c+d), which both equal 0.
a+b=0
c+d=0
Then a+b=0=c+d,
Thus, a+b=c+d
However, a+b+c+d=0
Thus, a+b=-c-d
Therefore, a+b=c+d AND a+b=-(c+d)
How is this possible?
Suppose we have 2 numbers, (a+b) and (c+d), which both equal 0.
a+b=0
c+d=0
Then a+b=0=c+d,
Thus, a+b=c+d
However, a+b+c+d=0
Thus, a+b=-c-d
Therefore, a+b=c+d AND a+b=-(c+d)
How is this possible?