Simple Calculus (indefinite integral)

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Homework Help Overview

The problem involves finding the indefinite integral of the function ∫ Cos32x Sin22x dx, which falls under the subject area of calculus, specifically integral calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to begin the problem. Some participants suggest using trigonometric identities to simplify the expression, while others mention substitution methods.

Discussion Status

The discussion includes various approaches to tackle the integral, with some participants providing identities and substitutions that could be useful. There is no explicit consensus, but several lines of reasoning are being explored.

Contextual Notes

Participants note the absence of specific homework equations and the original poster's request for guidance on how to initiate the solution process.

AryRezvani
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Homework Statement



Find the indefinite integral:
∫ Cos32x Sin22x dx

Homework Equations



None required

The Attempt at a Solution



Lost on where to start. If someone could just start me off.
 
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either use the identity
cos3(2x)sin2(2x)=(1/16) (2 cos(2 x)-cos(6 x)-cos(10 x))
or
cos3(2x)sin2(2x)=(1/2)(sin2(2 x)-sin4(2 x))(sin(2x))'
and the substitution u=sin(2x)
 
AryRezvani said:

Homework Statement



Find the indefinite integral:
∫ Cos32x Sin22x dx

Homework Equations



None required

The Attempt at a Solution



Lost on where to start. If someone could just start me off.
Write cos3(2x) as cos(2x) cos2(2x)

Then use the identity,
cos2(2x)=1-sin2(2x)​
After that, a simple substitution should work fine.
 
SammyS said:
Write cos3(2x) as cos(2x) cos2(2x)

Then use the identity,
cos2(2x)=1-sin2(2x)​
After that, a simple substitution should work fine.

Knocked it out, thanks guys.
 

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