Simple equation, but I dont know how to solve for x

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vaxop
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without using a calculator's graphing or equation solver tools :-p

2000x^16 + 5000x^39 = 3000 + 1600x^12
how can i solve for x?

200(1+i)^7 + 100(1+i)^5 = 300(1+i)^3
i?

1.06^t = 2(1.04)^t
t?

1.08^-n + 1.08^-2n = 1
n?

6x^2-2x-3=0
argh why can't i do these.. i feel like I am missing a basic technique that can be applied to all of these
 
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is it possible?
 
Last edited:
bumpbumpbump
 
As for the second, i=-1 is a solution.
To find the other solutions, divide throughout with (1+i)^3, and introduce z=(1+i)^2.
 
Are you sure you typed your first equation correctly?
 
I was also wondering about that one.
It is order of magnitudes more difficult to solve than the others.
 
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how about if the unkown is in the exponent
like..
1.06^t = 2(1.04)^t
t?

1.08^-n + 1.08^-2n = 1
n?
 
Use well-known logarithm rules for the first one, set x=1.08^{-n} in the second one.
 

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