Simple equation to calculate my initial velocity

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SUMMARY

The discussion centers on calculating initial velocity during a jump using basic physics equations. The key formula derived is v = sqrt(20h), where 'h' represents jump height, leading to an initial velocity of approximately 4.5 m/s for a 1-meter jump. Additionally, a weight reduction from 91kg to 81kg would increase jump height by about 10%, reaching approximately 1.1 meters. The conversation emphasizes that while basic laws of motion provide a framework, practical experimentation is essential for understanding bodily physics.

PREREQUISITES
  • Basic understanding of physics concepts such as kinetic and potential energy
  • Familiarity with the equations of motion, specifically s = ut + at²/2
  • Knowledge of gravitational acceleration (g) and its impact on motion
  • Ability to perform square root calculations
NEXT STEPS
  • Research the principles of kinetic and potential energy in physics
  • Learn more about the equations of motion and their applications in real-world scenarios
  • Explore the effects of body weight on jump dynamics and performance
  • Investigate experimental methods to measure jump height and velocity
USEFUL FOR

This discussion is beneficial for physics students, fitness enthusiasts, and anyone interested in understanding the mechanics of jumping and the effects of body weight on performance.

cdiener
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I am looking for a simple equation to calculate my initial velocity when I jump in layman's terms. For instance...if I weigh 91kg and jump 1 meter...what is my initial velocity and what would my maximum jump height be if I weighed 81kg? This is probably something I missed in freshman physics...but I was a business major and not too bright!
 
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the kinetic .5mv*v goes into Potential mgh
v*v=2gh
v=sqrt(20h)
so in ur example where h=1 then v is about 4.5m/s

if you lost 10kgs and had the same jump force you would go 91/81 higher, approx 1.1m
 
Your initial velocity is zero and your jump height is undetermined at this point. Bodily physics is best understood by experiment, applying basic laws of motion will not ever give you a useful model.

Do you mean maximum velocity? That can be determined easily. If you jump up a meter you jump down a meter and applying a basic law (s = ut + at^2/2) we have 1m = gt^2/2 => t = sqrt(2/g) seconds (double it for your total time in the air when jumping a meter).

The above poster is completely correct.

Although at 91kg, you are either an incredibly ripped individual or an alternative bodily form. In the latter case I recommend intense cycling.
 
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