Simple equivalent resistance question

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SUMMARY

The discussion focuses on calculating the minimum number of 2Ω resistors required to achieve an effective resistance of 1.5Ω. The solution involves connecting three 2Ω resistors in series with one 2Ω resistor in parallel, totaling four resistors. Participants emphasize the importance of understanding combinations of resistors, particularly how parallel connections yield fractional resistance values. A systematic approach, such as creating a table of combinations, is recommended for mastering similar problems.

PREREQUISITES
  • Understanding of Ohm's Law
  • Knowledge of series and parallel resistor combinations
  • Ability to calculate equivalent resistance
  • Familiarity with basic electrical concepts
NEXT STEPS
  • Practice calculating equivalent resistance for various resistor combinations
  • Learn about the effects of resistor tolerances on circuit performance
  • Explore advanced topics in circuit analysis, such as Thevenin's and Norton's theorems
  • Research online resources for objective-type electrical engineering problems
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Students studying electrical engineering, educators teaching circuit theory, and anyone preparing for exams involving resistor calculations.

shivam01anand
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Homework Statement



how many minimum no of resistances of eash 2Ω resistance can be connected to have an effective resistance of 1.5Ω

Homework Equations





The Attempt at a Solution



I tried to put 2 in parallel,series and different combinations.


After 5-10 mins of relentless trying i could not figure the answer[ I know it now ans=4 ( 3 in series with one in parallel)


My point being how to really get hold of this "type" of problem very quickly(objective type q).

and if its not too much could you point out some more similar questions to this on the internet for a grasp on this "Type" of question?

Thanks
 
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hi shivam01anand! :smile:
shivam01anand said:
My point being how to really get hold of this "type" of problem very quickly(objective type q).

you're looking for a factor of 3/4

you only get fractions from parallel, so start with 2 parallel to 1 (doesn't work), then 3 parallel to 1 (does work, in this case), then 4 parallel to 1, then 3 parallel to 2, and so on …

in fact, why not write out a table of all combinations now, up to say 7, to give you practice and to see how it works? :wink:
 

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