When an aircraft begins to nose up the effects of gravity begin to slow its velocity. By dividing 100% by 90 degrees you get the number 1.11. So for each 1 degree incline the force of gravity increases by 1.11%? So at 1 degree the force of gravity is 1.11% 45 degrees the force of gravity is 50% 90 degress the force of gravity is 100% -90 degress the force of gravity is -100% meaning it is accelerating the aircraft in the dive. So at 1 degree the effect would be .0111*Ma? at 45 degrees it would be .5*Ma? at 90 degrees it would be 1.0*Ma? Diving straight down at -90 degrees would be -1.0*Ma? I just want to make sure I am mathematically and theoretically correct. I don't need to use a sine wave or anything like that? Meaning the Sin of the angle determines the percentage effect.