Simple harmonic motion in an accelerating car

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EddiePhys
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There's a pendulum attached to a car accelerating with ##A##. I know I can find it's time period using the "effective" g method, but I want to find it from first principles.

My attempt:
##tan\theta = A/g##
Now I displace it by ##\alpha## giving ##mgsin(\theta+\alpha)-mAcos(\theta+\alpha) = ma##

Expanding this and using small angle approximations:

##gsin\theta+g\alpha cos\theta-Acos\theta + A\alpha sin\theta = a##

Where did I go wrong?
 
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Can you simplify your last equation with your first? Does the result look like ##\ddot\alpha\propto-\alpha##? If so, is the constant of proportionality what you expect from doing it the easy way? Is its sign right?
 
Ibix said:
Can you simplify your last equation with your first? Does the result look like ##\ddot\alpha\propto-\alpha##? If so, is the constant of proportionality what you expect from doing it the easy way? Is its sign right?

I got it. Thanks!