# Simple Harmonic Motion, platform and box

## Homework Statement

A platform moves up and down in SHM, with amplitude 0.035 m. Resting on top of the platform is a block of wood. What is the shortest period of motion for the platform so that the block will remain in constant contact with it?

## Homework Equations

a(t)=-A$$\omega$$^2cos($$\omega$$t+phase constant)
amax=A$$\omega$$

## The Attempt at a Solution

I didn't see how I could possibly use the first one with so many unknowns so I used amax=A$$\omega$$ and set amax=9.8 figuring that the amount couldn't be more than gravity otherwise the block and platform would separate (maybe I'm wrong in this).
And so I set 9.8=.035$$\omega$$ and solved (getting 280). The I used $$\omega$$=2$$\pi$$f and solving for f (getting 140/$$\pi$$) and then using f=1/T and solved for T getting .0224 which was incorrect.

## The Attempt at a Solution

Related Introductory Physics Homework Help News on Phys.org
ehild
Homework Helper
Check your formula for amax, it is not correct.

ehild

Oh, it came out funny. It's supposed to be amax=A x omega. Is this still incorrect? If it is, I really need to throw a fit about a refund.

ehild
Homework Helper
No, see the previous line. a must be m/s2, yours is m/s.

ehild