Simple Harmonic Motion with Springs that have Mass

Click For Summary
SUMMARY

This discussion focuses on the implications of mass in springs when analyzing simple harmonic motion. The participant highlights that a spring with mass requires consideration of its weight, leading to non-uniform extension along its length. They propose a model using Hooke's Law to derive a differential equation but express confusion regarding the effective mass and extension dynamics. The conversation also touches on the complexities of strain and moments within the material, suggesting that modeling these factors is crucial for accurate analysis.

PREREQUISITES
  • Understanding of Hooke's Law and its application in spring mechanics.
  • Familiarity with differential equations and their role in modeling physical systems.
  • Knowledge of material properties, particularly elasticity and strain in springs.
  • Basic concepts of simple harmonic motion and its mathematical representation.
NEXT STEPS
  • Explore the derivation of differential equations for springs with mass in simple harmonic motion.
  • Investigate the effects of material strain and moments on spring behavior under load.
  • Study the dynamics of rubber bands as a practical example of non-uniform tension and mass distribution.
  • Review advanced topics in elasticity theory to understand the implications of mass in spring systems.
USEFUL FOR

Students and professionals in physics, mechanical engineering, and materials science who are studying the dynamics of springs and simple harmonic motion, particularly in scenarios involving mass and elasticity.

simpleton
Messages
56
Reaction score
0
Hi all,

I recently learned about simple harmonic motion. In all the questions I have done, the springs are massless. I would like to know what happens when the spring has mass. I think that if the spring has mass, then the force in the spring will also have to counteract the weight of the spring itself. And I think the extension of the spring is also not uniform over the length of the spring.

My idea is something like this. Let's say the length of the spring is AB, where A is the topmost point and B is the bottommost point. Let X is a point between A and B. At this point, the segment AX will extend by some amount e that support the weight of XB and the hanging mass by Hooke's Law. Then we can use this relationship to write out some differential equation.

However, I think I have made fundamental mistake in my reasoning above. It seems that as X moves towards B, the effective hanging mass (the hanging mass + the segment XB) becomes lighter, and yet the extension of the segment AX will increase.

Can someone help me out? I am getting more and more confused.
 
Physics news on Phys.org
anyone?
 
I think it is too difficult to model the forces on each spring element and write out a solvable differential equation.

What really happens in a spring is there is strain in the metal (twisting in the cross section) as well as moments in the cross section, which have linearly increasing forces as long as you stay in the elastic region of the material.

You can try to figure something out with a rubber band, since it is easier to think about. The rubber stretches but the mass/length changes. The tension is not constant throughout the band since it is accelerating.

I could probably come up with some models and equations but its late now and I'm a bit tired. I hope this helps a little bit.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 11 ·
Replies
11
Views
15K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 76 ·
3
Replies
76
Views
7K