Period of a mass spring system with 2 spring of same K(vert)

[Simon George]

A mass attached to a spring is oscillating in Simple Harmonic Motion. If an other spring of same sprinc constant is attached parrallel to the other spring, what is the period of this new system (as a function of the initial period).

Here's what I did and have no idea if this is right:

For the first period, T1= 2*pi*sqrt(m/k)

For the second period, T2= 2*pi*sqrt(m/(2k))
T2=(2*pi*sqrt(m/k))/sqrt(2)
T2=T1/sqrt(2)

Is that right?

 

[jrmichler]

Sanity check:
Two springs in parallel are stiffer than either spring separately.
The stiffer the spring(s), the higher the natural frequency.
The higher the natural frequency, the shorter the period.

You can use a similar line of reasoning for changes in the mass.

And your math looks correct.