Find the equation of the curve for which the slope is (ln x)^2/x and passes through P(1, 2)
The Attempt at a Solution
Integrate (ln x)^2 = 1/2 Integral( ((ln x)^2) 2/x dx)
I get: 1/2 [((ln x)^3/3) + C]
Then solving for C, I get C=2
Then my final answer is (ln x)^3/6 + 2
The textbook says it is (ln x)^3/3 + 2.
I don't get it.