eleventhxhour
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Simplify
1) Simplify and state any restrictions on the variables:
$$\frac{3a-6}{a+2} ÷ \frac{a-2}{a+2} $$
This is what I did. Can someone tell me what I did wrong? Thanks.
$$\frac{3a-6}{a+2} ⋅ \frac{a+2}{a-2} $$
$$\frac{3a^2-12}{a^2-4}$$
$$\frac{(3a+6)(a-2)}{(a+2)(a-2)}$$
$$\frac{3a+6}{a+2}$$
$$3 + \frac{6}{2}$$
$$= 6$$
Here is another one where I got the wrong answer, but I'm not sure what I did wrong:
2) Simplify and state any restrictions on the variables:
$$\frac{2(x-2)}{9x^3} ⋅ \frac{12x^4}{2-x} $$
This is what I did:
$$\frac{-2(-x+2)}{9x^3} ⋅ \frac{12x^4}{2-x} $$
$$\frac{-2}{9x^3} ⋅ 12x^4 $$
$$\frac{-24x^4}{9x^3} $$
$$\frac{3x^3(-8x)}{3x^3(9)} $$
$$\frac{-8x}{9} $$
1) Simplify and state any restrictions on the variables:
$$\frac{3a-6}{a+2} ÷ \frac{a-2}{a+2} $$
This is what I did. Can someone tell me what I did wrong? Thanks.
$$\frac{3a-6}{a+2} ⋅ \frac{a+2}{a-2} $$
$$\frac{3a^2-12}{a^2-4}$$
$$\frac{(3a+6)(a-2)}{(a+2)(a-2)}$$
$$\frac{3a+6}{a+2}$$
$$3 + \frac{6}{2}$$
$$= 6$$
Here is another one where I got the wrong answer, but I'm not sure what I did wrong:
2) Simplify and state any restrictions on the variables:
$$\frac{2(x-2)}{9x^3} ⋅ \frac{12x^4}{2-x} $$
This is what I did:
$$\frac{-2(-x+2)}{9x^3} ⋅ \frac{12x^4}{2-x} $$
$$\frac{-2}{9x^3} ⋅ 12x^4 $$
$$\frac{-24x^4}{9x^3} $$
$$\frac{3x^3(-8x)}{3x^3(9)} $$
$$\frac{-8x}{9} $$
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