- #1

andrey21

- 476

- 0

**Sounds waves in a pipe of varying cross-section are described by the equation**

*V*

^{2}d/dx (1/A dAu/dx) = d

^{2}u/dt

^{2}

Where A = 0.2+0.3x

So first I substituted A into the equation:

*V*

^{2}d/dx (1/(0.2+0.3x) d(0.2+0.3x)u/dx) = d

^{2}u/dt

^{2}

*V*

^{2}d/dx (0.3u/(0.2+0.3x) du/dx) = d

^{2}u/dt

^{2}This is as far as I can get, any help would be fantastic.