Simplifying Fractions: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around simplifying a rational expression involving polynomials. The expression is \(\frac{3a(a^2-4ab+4b^2)}{6a^2(a^2+3ab-10b^2)}\), which includes quadratic terms in both the numerator and denominator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss attempts to factor the quadratics in the expression and explore potential cancellations. There are mentions of using techniques such as reverse foil and factoring hints provided by others. Some participants express frustration with the learning materials and seek clarity on the steps involved.

Discussion Status

Participants are actively engaging with the problem, sharing their attempts and suggesting factoring techniques. There is a collaborative atmosphere as they encourage each other to show their work and clarify misunderstandings. No consensus has been reached, but several productive lines of inquiry are being explored.

Contextual Notes

Some participants note that they are not currently in a homework context but are preparing for future studies in computer science, which adds a layer of urgency to their understanding of the material. There are reminders about adhering to homework rules despite the informal nature of the discussion.

Amaz1ng
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Homework Statement



Simplify:
[tex]\frac{3a(a^2-4ab+4b^2)}{6a^2(a^2+3ab-10b^2)}[/tex]

Homework Equations


The Attempt at a Solution



Tried factoring stuff out, etc. This "teach yourself albebra" book is getting more and more annoying. Even mathway.com can't solve them (which is what I used to see steps).
 
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Amaz1ng said:

Homework Statement



Simplify:
[tex]\frac{3a(a^2-4ab+4b^2)}{6a^2(a^2+3ab-10b^2)}[/tex]

Homework Equations





The Attempt at a Solution



Tried factoring stuff out, etc. This "teach yourself albebra" book is getting more and more annoying. Even mathway.com can't solve them (which is what I used to see steps).
Show us what you tried. This rational expression can be simplified a lot. Both quadratics can be factored to produce some cancellation, and the 3a and 6a2 factors can be factored as well.
 
Here's a little something to look at: 4b2 can be written as: (2b)2 ...

I think this has reverse foil written all over it.

:wink:
 
I tried several things the other day and got from one attempt:

[tex] <br /> \frac{b^3}{6a^3}<br /> [/tex]
 
Amaz1ng said:
I tried several things the other day and got from one attempt:

[tex] <br /> \frac{b^3}{6a^3}<br /> [/tex]

That's way off. You need to show us your steps as well. Let's first start by looking at the factor [tex]a^2-4ab+4b^2[/tex]
Can you factorize this using Omega_Prime's hint?
 
[tex] (a-2b)(a-2b)[/tex]

O_o
 
This is not homework either. I'm going for comp science soon...if I go in unable to do this stuff I'm going to be screwed.

So feel free to post the steps if you have an answer so I can get a bit better understanding. ;o

What do I do about the bottom?
 
Amaz1ng said:
[tex] (a-2b)(a-2b)[/tex]

O_o
Ok good! Now can you factorize the bottom too? Think about back when you were factorizing quadratics such as x2+5x+6=(x+3)(x+2), but this time we simply have extra terms in there, so x2+5xy+6y2 would be (x+3y)(x+2y).

Amaz1ng said:
This is not homework either. I'm going for comp science soon...if I go in unable to do this stuff I'm going to be screwed.

So feel free to post the steps if you have an answer so I can get a bit better understanding. ;o

What do I do about the bottom?

Whatever the reason, you still have to abide by the homework rules :-p
 
[tex] <br /> \frac{a-2b}{2a(a+5b)}[/tex]I'm speshal! :shy:
 
  • #10
Amaz1ng said:
[tex] <br /> \frac{a-2b}{2a(a+5b)}[/tex]


I'm speshal! :shy:

Yep :wink:
 

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