Simplifying Fractions: Step-by-Step Guide

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Amaz1ng
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Homework Statement



Simplify:
[tex]\frac{3a(a^2-4ab+4b^2)}{6a^2(a^2+3ab-10b^2)}[/tex]

Homework Equations


The Attempt at a Solution



Tried factoring stuff out, etc. This "teach yourself albebra" book is getting more and more annoying. Even mathway.com can't solve them (which is what I used to see steps).
 
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Amaz1ng said:

Homework Statement



Simplify:
[tex]\frac{3a(a^2-4ab+4b^2)}{6a^2(a^2+3ab-10b^2)}[/tex]

Homework Equations





The Attempt at a Solution



Tried factoring stuff out, etc. This "teach yourself albebra" book is getting more and more annoying. Even mathway.com can't solve them (which is what I used to see steps).
Show us what you tried. This rational expression can be simplified a lot. Both quadratics can be factored to produce some cancellation, and the 3a and 6a2 factors can be factored as well.
 
Here's a little something to look at: 4b2 can be written as: (2b)2 ...

I think this has reverse foil written all over it.

:wink:
 
I tried several things the other day and got from one attempt:

[tex] <br /> \frac{b^3}{6a^3}<br /> [/tex]
 
Amaz1ng said:
I tried several things the other day and got from one attempt:

[tex] <br /> \frac{b^3}{6a^3}<br /> [/tex]

That's way off. You need to show us your steps as well. Let's first start by looking at the factor [tex]a^2-4ab+4b^2[/tex]
Can you factorize this using Omega_Prime's hint?
 
[tex] (a-2b)(a-2b)[/tex]

O_o
 
This is not homework either. I'm going for comp science soon...if I go in unable to do this stuff I'm going to be screwed.

So feel free to post the steps if you have an answer so I can get a bit better understanding. ;o

What do I do about the bottom?
 
Amaz1ng said:
[tex] (a-2b)(a-2b)[/tex]

O_o
Ok good! Now can you factorize the bottom too? Think about back when you were factorizing quadratics such as x2+5x+6=(x+3)(x+2), but this time we simply have extra terms in there, so x2+5xy+6y2 would be (x+3y)(x+2y).

Amaz1ng said:
This is not homework either. I'm going for comp science soon...if I go in unable to do this stuff I'm going to be screwed.

So feel free to post the steps if you have an answer so I can get a bit better understanding. ;o

What do I do about the bottom?

Whatever the reason, you still have to abide by the homework rules :-p
 
[tex] <br /> \frac{a-2b}{2a(a+5b)}[/tex]I'm speshal! :shy: