Single Slit Problems: 750nm Light & 2.0um Width

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The discussion focuses on calculating the angle at which 750nm light creates a second minimum in a single-slit experiment with a width of 2.0um. The relevant equation is Sin(theta) = n(lambda)/w, where n is the minimum order. The user attempts to solve the equation but encounters a calculator error due to inputting a sine value greater than 1. Clarification is sought on the origin of the value 3x10^-6, which is incorrect for this calculation. The correct angle for the second minimum is determined to be 49 degrees.
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Homework Statement


At what angle will 750nm light produce a second minimum if the single-slit width is 2.0um

Homework Equations


Sin(theta)=n(lambda)/w

The Attempt at a Solution


This is what I got so far
(theta)=sin-1(3x10^-6/2x10^-6)

I don't understand why I keep getting error on my calculator, what am I doing wrong here please help
 
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Quantum Fizzics said:

Homework Statement


At what angle will 750nm light produce a second minimum if the single-slit width is 2.0um

Homework Equations


Sin(theta)=n(lambda)/w

The Attempt at a Solution


This is what I got so far
(theta)=sin-1(3x10^-6/2x10^-6)
the answer btw is 49degrees
 
Quantum Fizzics said:
I don't understand why I keep getting error on my calculator
It's because you are asking for an angle with sin > 1.
Where do you get 3x10^-6 from?
 
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