Skater. Angular Momentum. Velocity.

AI Thread Summary
When a skater pulls her arms in during a spin, her moment of inertia decreases due to a smaller radius. This decrease in moment of inertia leads to an increase in angular velocity, as angular momentum is conserved in the absence of external forces. The discussion clarifies that while angular momentum remains constant, the skater's velocity increases as a result of the reduced radius. Participants debated the effects of external forces, concluding that gravity does not affect angular momentum in this scenario. Ultimately, the correct answer is that angular momentum remains constant while angular velocity increases.
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Homework Statement



10. A skater brings her arms in close to her body during a spin. What is the effect on her
angular momentum and angular velocity?

A) Angular momentum increases, velocity increases.
B) Angular momentum decreases, velocity decreases.
C) Angular momentum remains constant, velocity increases.
D) There is insufficient information to tell what will happen

Homework Equations



L = Iω
ω = v / r

The Attempt at a Solution



By bringing her arms in closer, she is decreasing the radius of her moment of inertia. As "r" gets smaller, v gets larger so ω becomes larger. When ω becomes larger, L is larger too because they're directly proportional. I choose "A." Do you all agree?
 
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No. What external forces are at work here? (I assume friction is being ignored.)
 
PeachBanana said:
By bringing her arms in closer, she is decreasing the radius of her moment of inertia.
and what effect does that have on her moment of inertia?
 
tms - Erm, gravity?

rcgldr - I = Mr^2 for a point mass so that decreases I.

ω * r = v

I just said "r" decreased. Perhaps letter "B" is a better choice.
 
external forces
PeachBanana said:
gravity?
Yes, but is that affecting the angular momentum? If no external force is affecting angular momentum, then what usually happens with angular momentum.

what happens when skater pull in her arms
PeachBanana said:
I = Mr^2 for a point mass so that decreases I.
So what do you think happens with angular momentum?
 
rcgldr - When no external forces are acting, angular momentum is conserved. But if "I" decreases, "L" should too.
 
PeachBanana said:
rcgldr - When no external forces are acting, angular momentum is conserved. But if "I" decreases, "L" should too.
If angular momentum is conserved and "I" decreases, then what should happen with ω ?
 
Angular momentum must increase to compensate for that. I was thinking of "v" and not "ω." So if someone came along and pushed the skater, would that be an external force?

"C."
 
rcgldr said:
If angular momentum is conserved and "I" decreases, then what should happen with ω ?

PeachBanana said:
Angular momentum must increase to compensate for that.
Did you mean that angular velocity must increase (since angular momentum is conserved)?
 
  • #10
C.is correct:angular momentum remains constant,velocity increase because radius decrease...
 
  • #11
rcgldr - Yes. That's what I should have typed. Sorry about that.
 
  • #12
PeachBanana said:
tms - Erm, gravity?

Which is exactly countered by the force of the ice on the skater, thus no net external force. Unless, perhaps, the skater is boring a hole through the ice, but I think we can ignore that possibility.
 
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