Ski Jumper Soars 111.4 km/hr Down Slope

  • Thread starter Thread starter jap90
  • Start date Start date
  • Tags Tags
    Slope
AI Thread Summary
A ski jumper reaches a speed of 111.4 km/hr while descending a steep hill before launching off a horizontal ramp. After leaving the ramp, the jumper enters free-fall and the ground slopes downward at a 45-degree angle. The discussion seeks to determine the distance the skier will land down the slope after takeoff. Participants are encouraged to share their thoughts on relevant equations and any additional information needed to solve the problem. The thread emphasizes collaboration and adherence to forum posting rules.
jap90
Messages
4
Reaction score
0
A ski jumper acquires a speed of 111.4 km/hr by racing down a steep hill. He then lifts off into the air from a horizontal ramp. Beyond this ramp, the ground slopes downward at an angle of q = 45°. Assuming the skier is in free-fall motion after he leaves the ramp,at what distance down the slope does the skier land?
Any help would be greatly appreciated.
thanks
 
Physics news on Phys.org
Hey jap, welcome aboard!
You might want to take a look at posting rules for this forum.
What ideas do you have about this problem? What do you know? What are you looking for? What equations might you use? Will you need to find any other information along the way?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Projectile Motion - Skier & Ramp
Replies
5
Views
6K
How to calculate the kinematics of an object pushed up an inclinex plane?
Replies
7
Views
1K
Solving for Ski Jumper Takeoff Speed: Using Energy and Motion Equations
Replies
1
Views
2K
How Far Will a Skier Land After a Flying Ski Jump?
Replies
2
Views
5K
The end of a ski jump(projectile motion)
Replies
12
Views
7K
Downward Projectile Motion on an Inclined Plane
Replies
2
Views
6K
Find the final speed of a skier if he lands 145m down a 20 degree slope?
Replies
1
Views
2K
Constant Acceleration of a skier Problem
Replies
4
Views
2K
What Is the Distance a Skier Lands From a Ramp?
Replies
1
Views
1K
Ski Jump Ramp: Calculating Gravitational Work, Total Speed, and Air Drag
Replies
7
Views
2K

Hot Threads

Recent Insights

Back
Top